提取指定的字段的值并把并在同一行上

inanin

Number:  202960
SealPDFSroof:  8
SealDFASFedCID:  bagboea4b5abcbdpuzfrixfybulv5rjdbiacn4x5qchesciskno6gndeug76hncci
DealIDs:  []

ActivDatiFDon:  1449989 (19 weeks 2 days ago)
ExpirFDFDSation:  2999230 (in 1 year 5 weeks)

DealFDWeFDight:  0
VerifiedDealWeight:  0
InitiDalPledge:  0.14904816968160地下城3636L
ExpDectedDayReward:  0.000652372378地下城291255
ExpecteDdStoragePledge:  0.012756295514883934

Deadline:  26
Partition:  1
Number:  202961
SeaDlDDFSProof:  8
SealDFedFDCID:  bagboea4b5abca2bho5udzt7l7y3l74xsz3x5uaamzn5p5vni3qubuluasnrdemyq
DealIDs:  []

ActivFDFDSFation:  1449992 (19 weeks 2 days ago)
ExpirDFation:  2999251 (in 1 year 5 weeks)

DealWDSDFeight:  0
VerifieFDDFFdDealWeight:  0
InitialPFDledge:  0.14904809210412fdsdffdf
ExpeDFctedDayReward:  0.0006523702788659DFSDFDS
ExpFDectedStoragePledge:  0.012756203907722646fsdaf

Deadline:  27
Partition:  1

Number到Deadline的這一段，有N多這樣的段，最終的效果如下：
202960  26
202961  27

由于數據量龐大需要高效的方法

inanin

..........

legs

1. perl -nE'/Number:\s*(\N+)/?print"$1 ":/Deadline:\s*(\N+)/?say$1:_'

復制代碼

inanin

回復 3# legs

ls A0* 得到一下文件
A02323-a-s.txt
A04223-a-s.txt
A04523-a-s.txt
A04323-a-s.txt
A03323-a-s.txt


希望通過一條命令獲得以下文本
2323,4223,4523,4323,3323